Question

The distance travelled by a particle starting from rest and
moving with an acceleration 4/3 ms 2, in the third second is
​

Answer 1

Answer:

Distance covered in nth second,

S

n

=u+

2

1

a(2n−1);

=0+

2

1

×

3

4

(2×3−1)

=

2

1

×

3

4

×5=

3

10

m