The domain function of f(x)=1÷√|x|-x is
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the domain of the function f is (- ∞, 0) .....
because
if x ≥0 then |x| = x
and the function ...
f(x)= 1/√(|x|- x)
= 1/0
= undefined
and if x<0 then |x| = - x
and the function is
f(x) = 1/√(|x|-x)
=1/√ (- x -x)
=1/√(-2x) since x<0 so -2x is a positive number......
so here is your ans.........
because
if x ≥0 then |x| = x
and the function ...
f(x)= 1/√(|x|- x)
= 1/0
= undefined
and if x<0 then |x| = - x
and the function is
f(x) = 1/√(|x|-x)
=1/√ (- x -x)
=1/√(-2x) since x<0 so -2x is a positive number......
so here is your ans.........
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