Question

The driving force F of a mass m causes the car to accelerate. In a time t it travels a distance S and its speed increases from U to V. What is the useful work done by the car engine?
(a) Fs/t. (b) m(V-U) (c) Ft (d) m(v^2-u^2)/2
Show me working pls

Answer 1

Solve the following linear equation x/2-5=x/3-4

Answer 2

According to Work-Energy Theorem,

Work Done = Change in Kinetic Energy

= mV^2/2 - mU^2/2 = m(V^2 - U^2)/2

(D) is the correct option.