Question

The edge length of a fcc unit cell of a metal is 400 pm. If the molar mass of metal is 60.22 g mol–1, then the density of the unit cell (in g/cm3) is (Avogadro’s constant (NA) = 6.022 × 1023)

Answer 1

Answer:

density of the unit cell,d=6.25g/cm³

a=400pm=400×10^-10cm

m=60.22gmol^-1

NA=6.022×10²³mol^-1

For the FCC unit cell,Z=4

From this,

density,d=Z×M/NA×a³

d=4×60.22/6.022×10²³×(400×10^-10)³

d=4×6022/6022×10²²×(64×10^-24)

d=1/16×10^-2

d=25/4g/cm³

density=6.25g/cm³

Explanation:

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