Question

the edual sides of a triangle are
(x+6) cm and (5x-2) cm, If
the third side is (7x-4) Cm
finds x. then find the perimeter of
triangle ​

Answer 1

Answer:

Equal sides

x+6=5x-2

5x-x=6+2

4x=8

x=2

third side= 7x-4

=7×2-4

=10Cm

Hence Perimeter= 8+8+10=26Cm

Answer 2

two sides which are equal =

=(x+6) =(5x-2)

=x-5x=-2-6

=-4x=-8

x=-8/-4=2

all the sides are =

(2+6)=8cm,

(5×2-2)=8 cm and

(7×2-4) =10cm

therefore,

perimeter=(8+8+10) cm=26cm