Question

The electric field at a point due to a point charge is 300N/C and the electric potential at that point is 15J/C .Calculate the distance of the point from the charge and the magnitude of the charge

Answer 1

Explanation:

For point charge

E=V/r

Given

V=15J/C

E=300N/C

Distance from point charge, r=?

Point charge, q=?

r=V/E=15/300=0.05m

V=

4πε

0

r

q

q=4πε

0

rV

q=

9×10

9

1

×0.05×15

q=0.083×10

−9

C

q=0.083nC

plz mark it as brainliest answer