Question

the electric field due to a point charge is 30 N/C and the electric potential at that point is 15 J/C . calculate the distance of the point from the charge and the magnitude of the charge.​

Answer 1

Answer:

For point charge

E=V/r

Given

V=15J/C

E=30N/C

Distance from point charge, r=?

Point charge, q=?

r=V/E=15/30=0.5m

V=

4πε

0

r

q

q=4πε

0

rV

q=

9×10

9

1

×0.5×15

q=0.83×10

−9

C

q=0.83nC