Question

The electrostatic force between two
charges distance r apart in vacuum is F.
The force between the same charges
distance r/2 apart in a medium of
dielectric constant 2 is
(i) f/2(ii)2f(iii)f/4(iv)4f​

Answer 1

Answer:F/4

Explanation:

Answer 2

Given :

Radius = r/2

Dielectric constant = 2

To find :

The force between the charges of distance is r/2

Solution :

• The force between two electrostatic particles is given by

                    F = q₁q₂ / (r²×k4π∈₀)

• If radius is r and dielectric constant is 1, So q₁q₂ / (r²×4π∈₀)

• If radius is r/2 and dielectri constant is is 2

          F₁= q₁q₂ / ((r/2)²×2×4π∈₀)

          F₁ =2×[ q₁q₂ / (r²×4π∈₀)]

          F₁ = 2F

The electrostatic force between the particles is 2F