The elevation in boiling point of 0.1 molal solution of x in water is o. 1536degree Celsius.. What conclusion do you draw about the molecular state of x
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Chloropropane perhaps is optically active than chlorobutane .HOPE IT HELPS.
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Since X gives elevation in boiling point of water this means that X is soluble in water.
The water boils at 100° because its vapour pressure at this temperature becomes equal to one atmospheric pressure which is 1.013bar. The vapour pressure of an aqueous solution of X is less than 1.013bar at 100° and therefore the solution will not boil at 100°. In order to make the solution to boil, its temprature is increased so that its vapour pressure becomes equal to 1.013bar. Thus, boiling of a solution of X is greater than the boiling of pure water.
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