The end A of a line AB is 10 mm in front of VP and 20 mm above HP. The line is inclined at 30° to HP. It's front view makes 45° with XY. The top view (plan) length is 60 mm. Draw the projections. Find the true length and true inclinations with VP. Also locate the traces.
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Given:
The end A of a line AB is 10 mm in front of VP and 20 mm above HP
Top view = 60 mm
VP = 20 mm
The angle by which line is incident = 30°
Explanation:
- A projection is a linear transformation P from a vector space to itself such that {\P\circ P=P}. That is, whenever P is applied twice to any vector, it gives the same result as if it were applied once.
The true length and true inclinations with VP:
β = 55°
a'b' = 57
ab = 69
The projection for the same is in the image.
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Top view is 60 mm. Draw a perpendicular from the end of top view towards the vp. As the angle is 30 draw a line to join the predrawn perpendicular line now the true length is formed.As the tl is same for both hp and vp draw the same true length is drawn at hp.
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