Chemistry, asked by hdrc2544, 1 year ago

The energy of removal of an electron from a hydrogen like atom in an excited state is 3.4 ev. The de-broglie wave length (in ) associated with the electron is

Answers

Answered by malika83
2

E = hc/€

(€ = lemda i dont have that on my keyboard sorry)

E=3.4eV = 3.4 * 1.67 * 10^-19 joules

E.=5.6 * 10^-19 joules

h = 6.626 * 10^ -34 (plank constant)

c = 3 * 10^8 m/sec (speed of light)

putting these values in E = hc/€

5.6 * 10^-19 = 6.626 *10^-34 * 3 * 10^8 /

solve:

€ = 3.55 * 10^-7 meters

Hope my calculations n conversions r right.. but m sure bout the formula

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