The energy required to bring a charge =−8.8nC q=−8.8nC from far away to 5.5cm from a point charge Q is 13mJ. What is the potential at the final position of q?
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Answer:1.42*10^15 V
Explanation:
Va - Vb = Wa- Wb/q0
Va= -(Wa - Winfinity)electric force/q0
Va= ( Winfinity -Wa)electric force/q0
T h u s the absolute electric potential coin a in an electric field can be determined by the work done spacing unit positive charge from infinity to the given point a by the external force or the work done per unit positive charge ine displacing from a to infinity.
W infinity to a = q0Va
Va= 13*10^6/8.8*10^-9
1.42*10^15
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Answer:
Q. 8.What is Energy nbbvvvbnnbv. nnb
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