The energy stored by a 0.05µF capacitor with a voltage of 100V
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Explanation:
Battery is dc voltage.
Therefore the energy should be 1/2*C×V^2
10uf = 10× 10^-6=1 ×10^-5
100V^2 =1×10^4
The energy stored will be 0.05 J.
Not so much…
To store significative energy through capacitor we need higher value for the capacitor.
10mF will give 50J.
100mF : 500J ….
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