Question

The engine of a car applies a force of 4200n. If the mass of car is two metric ton and co efficient of friction is 0.1. The velocity acquired by car after 10 sec is

Answer 1

Force applied, F = 4200 N

mass, m = 2000 kg

friction coefficient, n = 0.1

Maximum friction, f = nmg = 0.1×2000×9.8 = 1960 N

Net force = F - f = 4200 - 1960 = 2240N

acceleration, a = net force / mass = 2240/2000 = 1.12 m/s^2

time = 10 sec

velocity = u + at = 0 + 1.12×10 = 11.2 m/s

The velocity acquired by car after 10 sec is 11.2 m/s.

Answer 2

Answer:

11.2 is the best answer