Question

The enthalpy changes for the following processes are listed
below :
Cl₂(g) → 2Cl(g), 242.3 kJ mol⁻¹
I₂(g) → 2I(g), 151.0 kJ mol⁻¹
ICl(g) → I(g) + Cl(g), 211.3 kJ mol⁻¹
I₂(s) → I2(g), 62.76 kJ mol⁻¹
Given that the standard states for iodine and chlorine are I₂(s)
and Cl2(g), the standard enthalpy of formation for ICl(g) is :
(a) +16.8 kJ mol⁻¹ (b) +244.8 kJ mol⁻¹
(c) –14.6 kJ mol⁻¹ (d) –16.8 kJ mol⁻¹

Answer 1

$\huge\bold\red{Answer:-}$

(d) –16.8 kJ mol⁻¹

Answer 2

$\huge{\underline{\mathbb{\red{Answer}}}}$

d) –16.8 kJ mol⁻¹

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