Question

The equation of the line passing through the point p(2,5) such that p bisects the part intercepted between the axes is
(A) 5x – 2y = 20
(B) 5x + 2y = 20
(C) 5x - 2y + 20 = 0
(D) 5x + 2y + 20 = 0
A
B​

Answer 1

Answer:

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Step-by-step explanation:

5x + 2y - 8 = 0

2y = -5x +8

y = (-5/2)x + 4

A line perpendicular to y = (-5/2)x + 4 would have a slope of

-1/(-5/2) = 2/5, which is the negative reciprocal of -5/2

Let this line be y = (2/5)x + b

Since it passes through (-5, -1),

(-1) = (2/5)(-5) + b

-1 = -2 + b

b = 1

Thus y = (2/5)x + 1