Question

the equation of the straight line whic bisects the intercepts made by the axes on the lines x+y=2 and 2x+3y=6 is

Answer 1

The equation of the straight line which bisects the intercepts made by the axes on the lines x+y=2 and 2x+3y=6 is x/2+y/2=1
 
X intercept=(2,0)

y intercept =(0,2)

mid point=(1,1)
x/3+y/2=1

X intercept=(3,0)

y intercept=(0,2) mid point=(3/2,1)

slope of straight line =0 equation of the line is
x=1

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Given lines are  x+y=2 and 2x+3y=6

so the intercepts are (2,0) and (0,2)
also (3,0) and (0,2)

So 

The equation of a straight line which bisects the intercepts made by the axes on the lines x+y=2 and 2x+3y=6 is given by the equation y=3-2

Answer y=1