Question

The equation x^(2)-ax+1=0 has real solutions the greater of which is 'r' Now let 'b' be a positive real number such that the greater solution of the equation x^(2)-bx+1=0 is sqrt(r).If a=79 then what is 'b'?​

Answer 1

Answer:

b=13.7753 or 78.999

Step-by-step explanation:

x^2-ax+1=0

as a = 79

then, x^2-79x+1=0

by solving by quadratic equation

x = 78.9873 or 0.0126603

then put these value in second equation

then on putting x = 78.9873

we get b = 78.999

on putting x=0.0126603

we get b= 13.7753

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