Question

The equation x^2-ax+b=0 and x^3-px+qx=0

Answer 1

Answer:

Step-by-step explanation:

p(x) = x³ - px + qx

q(x) = x² - ax + b

g(x) = cx + d

p(x) = q(x)(gx)

=> x³ - px + qx = (x² - ax + b)(cx + d)

=> x³ - px + qx = cx³ +x²(d -ca) + x(bc -ad)  + bd

Equating powers

c = 1

d - ca = 0

=> d - a = 0

=> d = a

=> g(x) = (x + a)