Question

The equation x square - 8 x + k equal zero has real and distinct root if

Answer 1

Step-by-step explanation:

Question:-

find the value of k of the equation x²-8x+k has real and distinct root

solution:-

eq:- x²-8x+k

a=1, b= -8 ,c =k

Given

equal zero has real and distinct root then D>0

so :-b²-4ac>0

(-8)²-4×1×k>0

64-4k>0

-4k>-64

k>-64/-4

k>16

Answer:- k>16