The equations of the tangents drawn from the origin to the circle x2 + y2 - 2rx- 2hy + h2=0 are
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The center of circle x2+y2−2rx−2hy+h2=0 or (x−r)2+(y−h)2=r2 is (r,h) and radius is r.
As x-coordinate of center is r and radius too is r, one of the tangent is x=0, the y-axis and as other tangent would be parallel to x-axis.
Further, as we are drawing tangent from origin i.e. (0,0), it can only be x-axis i.e. y=0.
As such, distance from center (r,h) to x=0 i.e. ±h=r.
Hence answer could be both (A) and (B).
As an example see the following graph.
graph{((x-5)^2+(y-5)^2-25)((x-5)^2+(y+5)^2-25)=0 [-19.92, 20.08, -9.76, 10.24]}
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~~~~ Thanks~~~
The center of circle x2+y2−2rx−2hy+h2=0 or (x−r)2+(y−h)2=r2 is (r,h) and radius is r.
As x-coordinate of center is r and radius too is r, one of the tangent is x=0, the y-axis and as other tangent would be parallel to x-axis.
Further, as we are drawing tangent from origin i.e. (0,0), it can only be x-axis i.e. y=0.
As such, distance from center (r,h) to x=0 i.e. ±h=r.
Hence answer could be both (A) and (B).
As an example see the following graph.
graph{((x-5)^2+(y-5)^2-25)((x-5)^2+(y+5)^2-25)=0 [-19.92, 20.08, -9.76, 10.24]}
....Plz mark me as brainliest.....
~~~~ Thanks~~~
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