Question

The equivalent conductivities of sodium benzoate and HCl at 250C are 82.4 and 426.16 Scm2equiv–1 respectively. If the transport numbers of benzoate and H+ ions are 0.392 and 0.821 in the above mentioned compounds, find the equivalent conductivity of benzoic acid at 250C.

Answer 1

Answer:

CH

3

COONa+HCl⟶CH

3

COOH+NaCl

λ

eq(CH

3

COOH)

∞

=λ

eq(CH

3

COONa)

∞

+λ

eq(HCl)

∞

−λ

eq(NaCl)

∞

λ

eq(CH

3

COOH)

∞

=91+425.16−126.8=389.71 ohm

−1

cm

2

eq

where λ

eq

∞

= Equivalence conductivity at infinitie dilution.

Hence, the correct answer is (C)