Chemistry, asked by cool21, 1 year ago

the equivalent weight of MnSO4 is half of its molecular weight when it is converted into a) Mn2O3 b) MnO2 c) MnO4 d) MnO4^2-


cool21: please answer my question as soon as possible

Answers

Answered by DRRAHUL
9
In MnSO4 oxidation number of Mn = + 2
we know,
equivalent weight = Molecular mass /n-factor

first of all you have to know,
what is n-factor

n - factor is number for a elements which denotes the change in number of oxidation state of that element .

here , said , equivalent weight is half of molecular weight .
e.g equivalent = Molecular weight/2
so, n-factor = 2

it means oxidation number of Mn+2 change with +2
e.g new oxidation number of Mn = +4
now, check which of the following have +4 oxidation number of Mn .
(b) option O.N of Mn = +4
so, (b ) is answer
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