Question

the extreme quartiles for a normal distribution are 20 and 50 respectively.find it's parameter
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Answer 1

Answer:

plz mark as briliantist

Step-by-step explanation:

Solution: We first need to sort the frequency data given to us before proceeding with the quartiles calculation –

Sorted Data – 5, 10, 15, 17, 18, 19, 20, 21, 25, 28

n(number of data points) = 10

Now, to find the quartiles, we use the logic that the first quartile lies halfway between the lowest value and the median; and the third quartile lies halfway between the median and the largest value.

First Quartile Q1 = n+14th term.

= 10+14th term = 2.75th term

= 2nd term + 0.75 × (3rd term – 2nd term)

= 10 + 0.75 × (15 – 10)

= 10 + 3.75

= 13.75

Third Quartile Q3 = 3(n+1)4th term.

= 3(10+1)4th term = 8.25th term

= 8th term + 0.25 × (9th term – 8th term)

= 21 + 0.25 × (25 – 21)

= 21 + 1

= 22

Using the values for Q1 and Q3, now we can calculate the Quartile Deviation and its coefficient as follows –

Quartile Deviation = Semi-Inter Quartile Range

= Q3–Q12

= 22–13.752

=8.252

= 4.125

Coefficient of Quartile Deviation

= Q3–Q1Q3+Q1×100

= 22–13.7522+13.75×100

= 8.2535.75×100

≈ 23.08

Answer 2

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