Question

the factors of 1 - 6 Z + 9 Z Square​

Answer 1

SOLUTION :

Given that,

${9z}^{2} - 6z + 1$

TO FIND :

The factors of the given equation.

PROCESS :

${9z}^{2} - (3 + 3)z + 1$

${9z}^{2} - 3z - 3z + 1$

Now let's take common number.

$3z(3z - 1) - 1(3z - 1)$

$(3z - 1)(3z - 1)$

Now, let's equate them with zero.

$3z - 1 = 0$

$3z = 1$

$z = \frac{1}{3}$

Similarly, for the other term,

$3z - 1 = 0$

$z = \frac{1}{3}$

Hence,

The required factors are 1/3 and 1/3

Answer 2

Answer:

9z^2 - 3z - 3z +1

3z(3z - 1) - 1(3z - 1)

(3z - 1) ( 3z - 1)

(3z -1)^2

Step-by-step explanation:

hope u understand......