The father age is six times his son age. Four years hence, the age of the father will be four times his son's age. Find the present age of the son and the father.
Answers
Answered by
13
let the present age of son be x
let father's age be y
a/q
y=6x. ......(I)
four years later
age of son = x+4
age of father =y+4
again a/q
y+4=4(x+4)
6x+4=4x+16
2x=12
x=6
therefore age of son = 6 years
and age of father = 6×6=36 years
hope this will be helpful
let father's age be y
a/q
y=6x. ......(I)
four years later
age of son = x+4
age of father =y+4
again a/q
y+4=4(x+4)
6x+4=4x+16
2x=12
x=6
therefore age of son = 6 years
and age of father = 6×6=36 years
hope this will be helpful
Answered by
1
Let x be the present age of father and y be the present age of son.
Four years hence, it has a relation by given condition,
(x+4) = 4(y+4)
x-4y = 14
x = 6y
On putting the value of x,
6y-4y = 12
2y = 12
y = 6
When y = 6 then x = 36.
Hence the present age of father is 36 years and age of son is 6 years.
Similar questions
Computer Science,
8 months ago
Computer Science,
8 months ago
Physics,
8 months ago
English,
1 year ago
Math,
1 year ago
Chemistry,
1 year ago
English,
1 year ago