Question

The father age is six times his son age. Four years hence, the age of the father will be four times his son's age. Find the present age of the son and the father.

Answer 1

let the present age of son be x
let father's age be y
a/q
y=6x. ......(I)
four years later
age of son = x+4
age of father =y+4
again a/q
y+4=4(x+4)
6x+4=4x+16
2x=12
x=6
therefore age of son = 6 years
and age of father = 6×6=36 years


hope this will be helpful

Answer 2

Let x be the present age of father and y be the present age of son.

Four years hence, it has a relation by given condition,

           (x+4) = 4(y+4)

            x-4y = 14

                 x = 6y

On putting the value of x,

        6y-4y = 12

             2y = 12

               y = 6

When y = 6 then x = 36.

Hence the present age of father is 36 years and age of son is 6 years.