Question

The father's age 10 years ago was 35 more than twice his son's age.
After how many years from now will the father be twice his son's age?
a) 15
b) 20 c) 25 d) 30​

Answer 1

Answer:

you answer is option (b)

Answer 2

Answer:

Let father's and son's age, 10 years ago, be f and s respectively.

From the given information,

f = 2s + 35... (i)

Present age of father = f + 10

Present age of son = s + 10

Let after x number of years, father be twice his son's age. Then, we have:

f + 10 + x = 2(s + 10 + x)

On simplifying, we get, x = f - 2s - 10

Using (i), we get,

x = 35 - 10 = 25

Thus, after 25 years father will be twice his son's age.

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