Math, asked by typhonjaatXwanda, 2 months ago

the father's age is 5/2 times of his daughters age 8 years ago it was four times of his daughters age find their present age​

Answers

Answered by chauhan95
1

sorry , I can't help you

sorry , again

Answered by akky0020
1

Answer:

Daughter age =16

Father age= 40

Step-by-step explanation:

Let daughter present age = x years

Then father's age =5/2(x)=5x/2

According to question

8 years ago

5x/2-8=4*(x-8)

5x-16=8x-64

8x-5x=64-16

3x=48

x=16

Father's age =5x/2=5*16/2

=40

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