Question

The figure shows a heavy block kept on a frictionless surface and being pulled by two ropes of equal mass m. At t = 0, the force on the left rope is withdrawn but the force on the right end continues to act. Let F1 and F2 be the magnitudes of the forces exerted by right rope and the left rope on the block, respectively.
Figure
(a) F1 = F2 = F for t < 0
(b) F1 = F2 = F + mg for t < 0
(c) F1 = F, F2 = F for t > 0
(d) F1 < F, F2 = F for t > 0

Answer 1

The conditions suggest that when t < 0 then both the forces are equal to F. i.e.  F1 = F2 = F

Option (A) is correct.

Explanation:

For t < 0

• Two forces were acting on the box, still it was at rest.
• This means that the forces were balanced.
• Hence, as shown in the figure.

• F1  = F 2
• Since, these have to be equal to the forces shown in the figure.
• F1 =F2  = F

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Thus the conditions suggest that when t <0 then both the forces are equal to F. i.e.  F1 = F2 = F

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Answer 2

t < 0, F1  = F = F2 .

Explanation:

A heavy block is shown in the figure. It is shown that on a frictionless surface, a heavy block is placed, and it is pulled by two ropes having equal mass. On the left rope, the force is withdrawn at $t=0$

At t < 0, in the horizontal direction, the block is in equilibrium.

So, $F_{1}=F=F_{2}$

$\text { At } t>0, F_{1}=F \text { and } F_{2}=0$