Question

The figure shows the running trac.The ends are semicircle of radius 42m each​

Answer 1

Answer:

Area = Ixb+πr^2 = 35x84+22x42^2/7

= 2940+5544=8484 m2. Ans

Answer 2

To Find the area of Running Track , we Need to sum of all the areas.

Area of the straight edges = Length × Breadth ( Since It is a rectangle , we can say so because It's length and breadth differ )

=> Length × Breadth

=> 35 × 84

=> 2940 m² ....(1)

There are two semi-circles in the running track of radius 42 m, Hence they are equal and congruent and by combining both, a circle of radius of 42 m is formed.

We know that,

Area of a circle = $\pi r^2$

=> $\frac{22}{\cancel{7}} \times \cancel{42} \: 6 \times 42$

=> $22 \times 6 \times 42$

=> 5544 m² ....(2)

By adding (1) and (2), We get the area of the running track.

Area of Running Track = (1) + (2)

=> 2940 + 5544

=> 8484 m²

Answer : 8484 m²