the first and last term of an Ap are 17 and 350 respectively. if c.d is 9 how many terms are there and what is their sums.
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a= 17
an= 350. d= 9
an = a +(n-1)d
350=17+(n-1)9
350-17=(n-1)9
333
—— =(n-1)
9
37+1 =n
38=n
Sn= n\2 (a+l)
=38\2(17 + 350)
=19 x 367
=6973
an= 350. d= 9
an = a +(n-1)d
350=17+(n-1)9
350-17=(n-1)9
333
—— =(n-1)
9
37+1 =n
38=n
Sn= n\2 (a+l)
=38\2(17 + 350)
=19 x 367
=6973
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