The first and last term of an AP are -4 and 146 .The sum of the terms is 7171. The number of terms is
a) 101 b) 100 c) 99 d) none of these
Pls answer its urgent
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option a see the attachment
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anjalianjalipillai:
This 4 the help
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Answered by
2
S=7171
S=n /2[2a+(n-1)d]=7171
n[a+a+(n-1)d]=7171(2)
n(-4+146)=7171(2)
n=7171/71=101
Option :(a)
S=n /2[2a+(n-1)d]=7171
n[a+a+(n-1)d]=7171(2)
n(-4+146)=7171(2)
n=7171/71=101
Option :(a)
Sry but ur answer is wrong
It's 101
Ur steps r right but 4got to multiple 7171*2
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