Question

The first and third terms of an A.P. {A1} are A1 = a and A3 = b, and a1 = a and a5 = b respectively be the first and fifth terms of another A.P. {a1}. Find the ratio of An+1 and a2n+1​

Answer 1

Answer is : 1

Step-by-step explanation:

For the first A.P. a + 2D1 = b i.e. D1= [b – a]/2.

For the second A.P. a + 4D2 = b i.e. D2 = [b – a]/4.

Now the value of An+1will be a + (n + 1 – 1) * [b – a]/2.

Similarly the value of a2n+1 will be a + (2n + 1 – 1) * [b – a]/4

. Taking the ratio of these two, we get:  1

Answer 2

Answer:

1:1

Step-by-step explanation:

first terms are equal

3 rd of first AP and 5th term of second AP are equal

n th  of first AP and 2n -1 th term of second AP are equal

n +1 th  of first AP and 2n +1 th term of second AP are equal

so ratio  of  An+1  : a2n+1​  = 1:1