Question

The first ionic radius of Cr is minimum in which of the following compounds?

1) K2CrO4 2) CrF3 3) CrO2 4) CrCl3

plzz answer with reason

Answer 1

Ionic radius of Cr depend on the oxidation state i.e higher the charge on the Cr atom smaller is the size of the Cr atom. 

Oxidation number of chromium in K2CrO4 is =+6

Oxidation number of chromium in CrF3  = +3

Oxidation number of chromium in CrO2  = +4

Oxidation number of chromium in CrCl3 = +3

Hence, The first ionic radius of Cr is minimum in K2CrO4

Answer 2

Explanation:

hey mate here is your answer

the correct answer is option no. 3