the first term of an ap is 5 and its 10 term is -292 find its 50 term
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first term is 5
10th term is -292
sn=a+(n-1)d
1st term = 5=a+d=5...........(I)
10th term = -292=a+9d=-292..............(ii)
on subtracting eqs.(I) and(ii),we get
we get d
then substitute d in eqs. (I)
we get a
then put the value of a and d in
a+49d
10th term is -292
sn=a+(n-1)d
1st term = 5=a+d=5...........(I)
10th term = -292=a+9d=-292..............(ii)
on subtracting eqs.(I) and(ii),we get
we get d
then substitute d in eqs. (I)
we get a
then put the value of a and d in
a+49d
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