Question

The first term of an AP is 6 and common difference is 5 find the AP and it's general term.

Answer 1

Answer:

first term of an AP , a = 6

common difference , d = 5

we know, general sequance of arithmetic progression is ; a , a + d, a + 2d, a + 3d....

so, A.P is ; 6, (6 + 5), (6 + 2 × 5), (6 + 3 × 5), .....

⇒AP is ; 6, 11, 16, 21, .....

general term, a_na

n

= a + (n - 1)d

= 6 + (n - 1)5

= 6 + 5n - 5

= 5n + 1

so, general term of given AP is (5n + 1), where n = 1, 2, 3, 4, 5, .....

you can verify it,

first term , a_1a

1

= 5 × 1 + 1 = 6

2nd term , a_2a

2

= 5 × 2 + 1 = 11

3rd term , a_3a

3

= 5 × 3 + 1 = 16

fourth term, a_4a

4

= 5 × 4 + 1 = 21

please mark it branlist

Answer 2

Answer:

the AP is 6,11,16,21,26.... and general term is 5n + 1

Step-by-step explanation:

for AP, first term= a = 6

second term = a+d = 6+5 = 11

third term = a+2d = 6+ 2*5 = 6+10 = 16 and so on you can find the AP

for general term, an = a+(n-1)d = 6 +(n-1)5

                                                  = 6 +5n-5

                                                  = 5n-1