the floor of rectangular hall has perimeter 250 m if the cost of painting the four walls @ rupees 10 per metre square is rupees 15000 find the height of the hall
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Given that cost of the rectangular hall = 15000.
Given that cost per m^2 = 250 m.
Given that perimeter = 250m.
2(l + b) = 250m.
Then the area of the 4 walls = 2 * (l + b) * h
= 250 * h
= 250h.
Given that rate of the hall per m^2 = 10.
Then the cost of painting the 4 walls = 10 * 250h
15000 = 10 * 250h
h = 15000/250 * 10
h = 15000/2500
h = 6.
Therefore the height of the hall = 6m.
Hope this helps!
Given that cost per m^2 = 250 m.
Given that perimeter = 250m.
2(l + b) = 250m.
Then the area of the 4 walls = 2 * (l + b) * h
= 250 * h
= 250h.
Given that rate of the hall per m^2 = 10.
Then the cost of painting the 4 walls = 10 * 250h
15000 = 10 * 250h
h = 15000/250 * 10
h = 15000/2500
h = 6.
Therefore the height of the hall = 6m.
Hope this helps!
Answered by
2
Step-by-step explanation:
Let length, breadth, and height of the rectangular hall be l, b, and h respectively.
Area of four walls = 2lh+2bh
= 2(l+b)h
Perimeter of the floor of hall = 2(l+b)
= 250 m
Area of four walls = 2(l+b) h = 250h m2
Cost of painting per square meter area = Rs.10
Cost of painting 250h square meter area = Rs (250h×10) = Rs.2500h
However, it is given that the cost of paining the walls is Rs. 15000.
15000 = 2500h
Or h = 6
Therefore, the height of the hall is 6 m.
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