The focal length of an equiconvex lens is equal to the radius of curvature either face.what is the refractive kndex of the material of the lens
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focal length= 1/f = (μ-1)(1/r1 + 1/r2)
It is given that r2 = r1 = f= r
so, 1/r = (μ-1)(1/r + 1/r)
μ= 1/2 + 1 = 3/2 =1.5
It is given that r2 = r1 = f= r
so, 1/r = (μ-1)(1/r + 1/r)
μ= 1/2 + 1 = 3/2 =1.5
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Hyy here is ur answer
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