Question

The focal light of aconvace lens is 30. Where should an objectbe placed so that its image is1/10 of its size

Answer 1

Answer:

Explanation:

1/10=-v/u

Therefore

-10v = u            -i)

Now using mirror formula,i.e,

1/v+1/u=1/f

Putting values from i)

Therefore,

1/v-1/10v =1/f

10-1/10v = 1/30

9/10v = 1/30

9×30/10=v

27 units = v

Therefore u= -10×27= -270 units

Hence,

It should be kept -270 units ahead of the mirror

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