Science, asked by vedanti815, 1 year ago

The following are the heats of reactions -
(i) ∆H; of H20 = -68.3 kCal mol-1
(ii) ∆HComb. of C2H2= -337.2 kCal mol-1
(iii) ∆HComb. of C,2H,4= -363.7 kCal mol-1
Then heat change for the reaction
C2H2, + H,2 ---C2H4 is -
(1) -716.1 kCal
(2) + 337.2 kCal
(3) -41.8 kCal
(4) -579.5 kCal​

Answers

Answered by tyth
0
The answer of your question is c right answer
Answered by ItzDαrkHσrsє
1

Answer:

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