Question

The following equations give the position x(t) of a particle in four situations in each equation, x is in meters, t is in seconds, and t > 0):(1) x = 3t - 2; (2) x = -412 - 2; (3) x = 2/12; and (4) x = -2. (a) In which situation is the velocity v of the particle con- stant? (b) In which is v in the negative x direction?​

Answer 1

Answer:

9

3x

2

+ax−2=0

Since, one root is 1, then x=1

⇒ 3(1)

2

+a(1)−2=0

⇒ 3+a−2=0

⇒ a+1=0

⇒ a=−1

⇒ Now, it is given that ax

2

+6ax−b=0 has equal roots.

∴ b

2

−4ac=0

⇒ (6a)

2

−4(a)(−b)=0

⇒ 36a

2

+4ab=0

⇒ 36(−1)

2

+4(−1)b=0 [ Substituting a=−1 ]

⇒ 36−4b=0

⇒ 4b=36

∴ b=9

Answer 2

Answer:

Step-by-step explanation:

w