Question

The force experienced by a proton placed in an upward electric field of 4*10^4NC^-1 is what

Answer 1

The force experienced by a proton placed in an upward electric field of 4 × 10⁴ N/C is 6.4 × 10⁻¹⁵ N

Explanation:

Given the electric field

$E=4\times 10^4$ N/C

We know that force experienced by a charge q in an electric field E is given by

$F=qE$

Charge on a proton

$q=1.6\times 10^{-19}$ C

Therefore, the force on proton

$F=1.6\times 10^{-19}\times 4\times 10^4$ N

$\implies F=6.4\times 10^{-15}$ N

Hope this answer is helpful.

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