the formula for nth term is a+[n-1]d.if 6th term is 10 and the 9th term is 13.then find 25th term
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first ,find two equations then find the first term and tgen put all the values to get the 25th term
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plakshmireddy20:
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Given :- a6 = 10
a + ( n - 1 )d = 10
a + 5d = 10 ......... ( i )
a9 = 13
a + 8d = 13 ....... ( ii )
Sub ( ii ) from ( i )
a + 5d - ( a + 8d ) = 10 - 13
a + 5d - a - 8d = -3
- 3d = - 3
d = 1
Putting the value of d in equation ( i )
a + 5d = 10
a + 5 × 1 = 10
a + 5 = 10
a = 10 - 5
a = 5
Now
a25 = a + ( n - 1 )d
a25 = 5 + ( 24 - 1 )×1
a25 = 5 + 23
a25 = 28
So, the 25th term is 28
a + ( n - 1 )d = 10
a + 5d = 10 ......... ( i )
a9 = 13
a + 8d = 13 ....... ( ii )
Sub ( ii ) from ( i )
a + 5d - ( a + 8d ) = 10 - 13
a + 5d - a - 8d = -3
- 3d = - 3
d = 1
Putting the value of d in equation ( i )
a + 5d = 10
a + 5 × 1 = 10
a + 5 = 10
a = 10 - 5
a = 5
Now
a25 = a + ( n - 1 )d
a25 = 5 + ( 24 - 1 )×1
a25 = 5 + 23
a25 = 28
So, the 25th term is 28
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