the frezing point of aqueous solution contains 5% by mass urea, 1% by mass kcl and 10% by mass glucose is
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Explanation:
Mass of solution = 100 g
Mass of glucose = 10 g; Mass of urea = 5g
Therefore mass of water= (100-10-5) =85g
Total number of moles of solutes =
Effective Molality of solution =
Tb = Kf x m = 1.86 x 1.31 = 2.43
Hence the freezing point = 0- 2.43 = - 2.43oC.
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