Question

the frezing point of aqueous solution contains 5% by mass urea, 1% by mass kcl and 10% by mass glucose is

Answer 1

Explanation:

Mass of solution = 100 g

Mass of glucose = 10 g; Mass of urea = 5g

Therefore mass of water= (100-10-5) =85g

Total number of moles of solutes =

Effective Molality of solution =

Tb = Kf x m = 1.86 x 1.31 = 2.43

Hence the freezing point = 0- 2.43 = - 2.43oC.