the GCF of two numbers is 23 their product is 55545
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since the gcd of both no's is 23, so it is clear that each no. is multiple of 23 and 23 is also a prime no. so it has to be two times in the factors of 55545 i.e. 3*5*23*23*7
now the no's must be multiple of 23 then we will find two combination of no's from above given factors such that multiply of both must be 55545
so the no's are let a and b then
a= 3*5*23 =345
b= 7*23 = 161
proof:
a*b = 55545
if you try yourself, may be you find optimal solution of this problem.
now the no's must be multiple of 23 then we will find two combination of no's from above given factors such that multiply of both must be 55545
so the no's are let a and b then
a= 3*5*23 =345
b= 7*23 = 161
proof:
a*b = 55545
if you try yourself, may be you find optimal solution of this problem.
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