the graphof equations 2x - y - 4 =0 and X + Y + 1 =0 intersect at point p(a,b) what is the coordinate of p
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Answer:
point P(1, -2)
Step-by-step explanation:
2x – y – 4 = 0-------eqn1
x + y + 1 = 0 ---------eqn2
add eqn1+ eqn2, we get
2x-y-4+x+y+1=0+0
3x-3=0
3x=3
x=1
sub x=1 in eqn1, we get
2*1-y-4=0
2-y-4=0
-y-2=0
-y=2
y= -2
point P(1, -2)
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