the gravitational force between two bodies is decreased by 36% when the distance between them is increased by 3m.the initial distance between them is
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F∝1d2,given F′=64F100F,d′=(d+3) ∴FF′=(d+3)2d2 ⇒64F100F=d2(d+3)3⇒810=dd+3 8d+24=10d 2d=24⇒d=12m
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two bodies decreased=36%. increased=3m initial distance them is 3×36÷100=108÷100=1.08m
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