the gravitational force between two object is f how will this force change where the distance is quadruple and its mass is doubled
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F = GMm / d²
From above
F ∝ Mm / d²
F₂ = F₁ × (2Mm / Mm) × (d² / (16d²)
= F₁ / 8
Final force will be 1/8 times that of initial.
From above
F ∝ Mm / d²
F₂ = F₁ × (2Mm / Mm) × (d² / (16d²)
= F₁ / 8
Final force will be 1/8 times that of initial.
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