The greatest number which will divide 43, 91 and 183 so as to leave the same remainder in each case is………………
2 pointsSamir wants to organize his marbles by putting them in bags. If he places 3 marbles in each bag, he has 2 left. If he places 4 marbles in each bag, he has 2 left. If he places 5 marbles in each bag, he has 2 left. The minimum number of marbles Samir has _________________.
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If , 12 x 12 = 9 23 x 23 = 16 34 x 34 = ………. The value of 34 x 34 is
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Here, we need to find differences between the given numbers. If two numbers give the same remainder when divided by some other number, then their difference must give a remainder of zero when divided by that number.
Our numbers here are 91−43=48,183−91=92,183−43=140
So we have the set of numbers {48,92,140} and we want to know the biggest number that divides all these numbers.
So,
48=2×2×2×3
92=2×2×23
140=2×2×5×7
The greatest common divisor of {48,92,140} is 4.
So, answer is 4.
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