the H C F of the following numbers using prime factorisation 27,63 and 54
Answers
Answered by
13
27=3*3*3
63=3*3*7
54=3*3*3*2
therefore their h.c.f is 9
63=3*3*7
54=3*3*3*2
therefore their h.c.f is 9
Answered by
6
27=3×3×3
63= 3×3×7
54=2×3×3×3
therefore the hcf(27,63,54)=
63= 3×3×7
54=2×3×3×3
therefore the hcf(27,63,54)=
smarty2333:
answer is 9
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